Class IX Math NCERT Solution for Surface Areas and Volumes 13.3

EXERCISE 13.3 (Page 221)
Q1.   Diameter of the be of a cone is 10.5 cm and its slant height is 10 cm. Find its curved surface area.
Sol: Here, diameter of the base = 10.5 cm
           
Q2.   Find the total surfce area of a cone, if its slant height is 21 m and diameter of its base is 24 m.
Q3.   Curved surface area of a cone is 308 cm' and its slant height is 14 cm. Find: (i) radius of the base and (ii) total surface area of the cone.
Sol: Here, curved surface area = 308 cm2 Slant height (1) = 14 cm
                 (i) Let the radius of the base be 'r' cm.
                 ∴ πrl = 308
                 
                 and curved surface area = 308 cm2
                 ∴ Total surface area = [Curved surface area] + [Base area]
                 = 308 cm2 + 154 cm2
                 = 462 cm2
Q4.   A conical tent is 10 m high and the radius of its base
           (i) slppnt height of the tent.
           (ii) cost, of the canvas required to make the tent, if the cost of 1 m2 canvas is Rs. 70.
Sol: Here, height of the tent (h) = 10 m
           Radius of the base (r) = 24 m
           
Q5.   What length of tarpaulin 3 m wide will be required to make conical tent of height 8 m and base radius 6 m? Assume that the extra length of material that will be required for stitching margins and wastage in cutting is approximately 20 cm (Use π = 3.14).
Sol: Here, Base radius (r) = 6 m
           Height (h) = 8 m
           
           ∴ Area of the canvas (tarpaulin) required to make the tent = 188.4 m2
           Let the length of the tarpaulin = 'L' m
           ∴ Length × Breadth = 188.4
           ⇒ L × 3 = 188.4
           
Q6.   The slant height and base diameter of a conical tomb are 25 m and 14 m respectively. Find the cost of white washing its curved surface at the rate of Rs. 210 per 100 m2.
Q7.   A joker's cap is in the form of a right circular cone of base radius 7 cm and height 24 cm. Find the area of the sheet required to make 10 such caps.
Sol: Here,
           Radius of the base (r) = 7 cm
           height (h) = 24 cm
           
           Lateral surface area of 10 caps = 10 × 550 cm2 = 5500 cm2
           Thus, the required area of the sheet = 5500 cm2
Q8.   A bus stop is barricaded from the remaining part of the road, by using 50 hollow cones made of recycled cardboard. Each cone has a base diameter of 40 cm and height 1 m. If the outer side of each of the cones is to be painted and the cost of painting is f 12 per m2, what will be the cost of painting ail the cones? (Use π = 3.14 and take 
Sol: Here,
           ∵ Diameter of the base = 40 cm
           
           

Comments

Popular posts from this blog

Class IX Math NCERT Solution for Circles 10.5

Class IX Math NCERT Solution for Heron’s Formula 12.2

Class IX Math NCERT Solution for Surface Areas and Volumes 13.5